0=-0.001x^2+.26x

Solution for 0=-0.001x^2+.26x equation:

0=-0.001x^2+.26x

We move all terms to the left:

0-(-0.001x^2+.26x)=0

We add all the numbers together, and all the variables

-(-0.001x^2+.26x)=0

We get rid of parentheses

0.001x^2-.26x=0

We add all the numbers together, and all the variables

0.001x^2-0.26x=0

a = 0.001; b = -0.26; c = 0;
Δ = b2-4ac
Δ = -0.262-4·0.001·0
Δ = 0.0676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.26)-\sqrt{0.0676}}{2*0.001}=\frac{0.26-\sqrt{0.0676}}{0.002}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.26)+\sqrt{0.0676}}{2*0.001}=\frac{0.26+\sqrt{0.0676}}{0.002}
$